Last week, I broke down the race for the top four seeds in the Big Ten because finishing in that group guarantees those teams a double-bye in the upcoming Big Ten Tournament. Heading into the final weekend of the regular season, we have a much clearer picture of this race. Wisconsin and Maryland have already locked up the #1 and #2 seeds, but the #3 and #4 seeds are still very much up in the air. Currently, there is a four-way tie for third place between Iowa, Michigan State, Ohio State, and Purdue. All teams have a record of 11-6 with one game remaining — none of which are against each other. This means that there are 16 possible (and very confusing) combinations of outcomes from this weekend’s games. To help clear things up, I created a cheat sheet showing where each team will be seeded given each scenario. The table below displays the 16 possibilities: Michigan State gets a double-by in 12 of the 16 options; Purdue in nine; Iowa in six; and, Ohio State in five.
Below is a synopsis for each team:
- Michigan State. Thanks to a 3-0 record against the other three teams, the Spartans would win all of the tiebreakers and end up with a top four seed in 12 of the sixteen scenarios and with the #3 seed in nine of the 16 scenarios. It breaks down like this: If the Spartans beat Indiana on the road, they’ll lock up the #3 seed; if they lose, they’ll need at least two other teams to also fall to get the double-bye. In this four-team race, Michigan State clearly has the upper hand.
- Iowa. The Hawkeyes finish with a top four seed in six of the 16 possible scenarios. In head-to-head tiebreakers, they will have the advantage over Ohio State (2-0) but not against the other two teams (0-1). In situations where multiple teams are tied, Iowa is hurt by its two losses to Wisconsin because the others only have one loss from the Badgers.